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Edit detail for #292 integrate(sin(x)**2) problem revision 1 of 10

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Time: 2007/11/17 22:22:16 GMT-8
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integrate(sin(x)**2,x=0..1) returns "potentialPole".   This doesn't look right.  We have integrate(sin(x)**2,x)=(t-cos(t)sin(t))/2; no pole.

Submitted by : (unknown) at: 2007-11-17T22:22:16-08:00 (16 years ago)
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integrate(sin(x)2,x=0..1) returns "potentialPole". This doesn't look right. We have integrate(sin(x)2,x)=(t-cos(t)sin(t))/2; no pole.