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Submitted by : kratt6 at: 2009-01-13T16:08:03-08:00 (8 years ago)
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Hm, it seems unreproducible here. It is reproducible on my machine, though...

fricas
f := operator 'f

\label{eq1}f(1)
fricas
count(true, [(product(product(f j, j=1..i), i=1..n)=product(product(f k, k=1..j), j=1..n))@Boolean for m in 1..200])

\label{eq2}200(2)

fixed in FriCAS revision 573 --kratt6, Fri, 10 Apr 2009 03:08:14 -0700 reply
Status: open => fixed somewhere

Status: fixed somewhere => closed




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