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last edited 10 years ago by test1 |
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last edited 10 years ago by test1 |
![\label{eq2}\begin{array}{@{}l}
\displaystyle
\left[{x ={2 \ {\arctan \left({\%x 0}\right)}}}, \:{x ={2 \ {\arctan \left({\%x 1}\right)}}}, \: \right.
\
\
\displaystyle
\left.{
\begin{array}{@{}l}
\displaystyle
x ={2 \ {\arctan{\left({{{\sqrt{-{{27}\ {{\%x 1}^{2}}}+{{\left(-{{18}\ \%x 0}-{30}\right)}\ \%x 1}-{{27}\ {{\%x 0}^{2}}}-{{3
0}\ \%x 0}+{37}}}-{3 \ \%x 1}-{3 \ \%x 0}- 5}\over 6}\right)}}}](images/7016209904719319189-16.0px.png "\label{eq2}\begin{array}{@{}l}
\displaystyle
\left[{x ={2 \ {\arctan \left({\%x 0}\right)}}}, \:{x ={2 \ {\arctan \left({\%x 1}\right)}}}, \: \right.
\
\
\displaystyle
\left.{
\begin{array}{@{}l}
\displaystyle
x ={2 \ {\arctan{\left({{{\sqrt{-{{27}\ {{\%x 1}^{2}}}+{{\left(-{{18}\ \%x 0}-{30}\right)}\ \%x 1}-{{27}\ {{\%x 0}^{2}}}-{{3
0}\ \%x 0}+{37}}}-{3 \ \%x 1}-{3 \ \%x 0}- 5}\over 6}\right)}}}")
![\label{eq3}\left[{{\log \left({{{{\left({{x}^{2}}- a \right)}\ {\sqrt{- a}}}+{2 \ a \ x}}\over{{{x}^{2}}+ a}}\right)}\over{2 \ {\sqrt{- a}}}}, \:{{\arctan \left({{x \ {\sqrt{a}}}\over a}\right)}\over{\sqrt{a}}}\right]](images/4613633913553793794-16.0px.png "\label{eq3}\left[{{\log \left({{{{\left({{x}^{2}}- a \right)}\ {\sqrt{- a}}}+{2 \ a \ x}}\over{{{x}^{2}}+ a}}\right)}\over{2 \ {\sqrt{- a}}}}, \:{{\arctan \left({{x \ {\sqrt{a}}}\over a}\right)}\over{\sqrt{a}}}\right]")