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This page is set to execute \begin{axiom}... \end{axiom} commands using FriCAS:

axiom

)version

Value = "Sunday November 1, 2009 at 20:31:03 "

Any comments added here with use this version of FriCAS.

... --meliusja, Tue, 08 Apr 2008 10:38:33 -0700 reply

axiom

solve(s=vt+at^2/2,t)

$\label{eq1}\left[ \right]$

(1)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:39:28 -0700 reply

axiom

radicalsolve(s=vt+at^2/2,t)

   There are no library operations named radicalsolve
      Use HyperDoc Browse or issue
                            )what op radicalsolve
      to learn if there is any operation containing " radicalsolve " in
      its name.

   Cannot find a definition or applicable library operation named
      radicalsolve with argument type(s)
                   Equation(Polynomial(Fraction(Integer)))
                                 Variable(t)

      Perhaps you should use "@" to indicate the required return type,
      or "$" to specify which version of the function you need.

... --meliusja, Tue, 08 Apr 2008 10:40:28 -0700 reply

axiom

solve(vt+at^2/2-s=0,t)

$\label{eq2}\left[ \right]$

(2)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:41:13 -0700 reply

axiom

solve(vt+at/2-s=0,t)

$\label{eq3}\left[ \right]$

(3)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:42:11 -0700 reply

axiom

solve(v*t+a*t/2-s=0,t)

$\label{eq4}\left[{t ={{2 \ s}\over{{2 \ v}+ a}}}\right]$

(4)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:42:37 -0700 reply

axiom

solve(v*t+a*t^2/2-s=0,t)

$\label{eq5}\left[{{{2 \ t \ v}+{a \ {t^2}}-{2 \ s}}= 0}\right]$

(5)

Type: List(Equation(Fraction(Polynomial(Integer))))

axiom

radicalSolve(p^3 - p + 1/10=0,p)

$\label{eq6}\begin{array}{@{}l} \displaystyle \left[{p ={{{{\left(-{3 \ {\sqrt{- 3}}}+ 3 \right)}\ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}^2}}- 2}\over{{\left({3 \ {\sqrt{- 3}}}+ 3 \right)}\ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}, \: \right. \ \ \displaystyle \left.{p ={{{{\left(-{3 \ {\sqrt{- 3}}}- 3 \right)}\ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}^2}}+ 2}\over{{\left({3 \ {\sqrt{- 3}}}- 3 \right)}\ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}, \: \right. \ \ \displaystyle \left.{p ={{{3 \ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{37 3}}}}\over{{60}\ {\sqrt{3}}}}}^2}}+ 1}\over{3 \ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}\right]$

(6)

Type: List(Equation(Expression(Integer)))

Subject: Be Bold !!

	( 7 subscribers )