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Edit detail for StructuredTables revision 5 of 5

1 2 3 4 5
Editor: kratt6
Time: 2008/01/20 11:54:40 GMT-8
Note: correct indentation

changed:
- CT := CARTEN(i0 := 1,3,Integer)
- epsilon:CT:=leviCivitaSymbol()
CT := CARTEN(i0 := 1,3,Integer)
epsilon:CT:=leviCivitaSymbol()

fricas
P:= [[1,0,0],[0,1,0],[0,0,0]]

\label{eq1}\left[{\left[ 1, \: 0, \: 0 \right]}, \:{\left[ 0, \: 1, \: 0 \right]}, \:{\left[ 0, \: 0, \: 0 \right]}\right](1)
Type: List(List(NonNegativeInteger?))
fricas
Q:= [[0,0,0],[0,0,0],[0,0,1]]

\label{eq2}\left[{\left[ 0, \: 0, \: 0 \right]}, \:{\left[ 0, \: 0, \: 0 \right]}, \:{\left[ 0, \: 0, \: 1 \right]}\right](2)
Type: List(List(NonNegativeInteger?))
fricas
CT := CARTEN(i0 := 1,3,Integer)

\label{eq3}\hbox{\axiomType{CartesianTensor}\ } (1, 3, \hbox{\axiomType{Integer}\ })(3)
Type: Type
fricas
epsilon:CT:=leviCivitaSymbol()

\label{eq4}\begin{array}{@{}l}
\displaystyle
\left[{\left[ 
\begin{array}{ccc}
0 & 0 & 0 
\
0 & 0 & 1 
\
0 & - 1 & 0 
(4)
Type: CartesianTensor?(1,3,Integer)
fricas
permi1:= matrix[[e0,0,0],[0,e0,0],[0,0,e0]]

\label{eq5}\left[ 
\begin{array}{ccc}
e 0 & 0 & 0 
\
0 & e 0 & 0 
\
0 & 0 & e 0 
(5)
Type: Matrix(Polynomial(Integer))
fricas
permi2:= matrix[[e11,e12,e13],[e12,e22,e23],[e13,e23,e33]]

\label{eq6}\left[ 
\begin{array}{ccc}
e 11 & e 12 & e 13 
\
e 12 & e 22 & e 23 
\
e 13 & e 23 & e 33 
(6)
Type: Matrix(Polynomial(Integer))