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Edit detail for Symbolic Integration revision 7 of 15

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Editor: test1
Time: 2015/06/30 18:12:55 GMT+0
Note:

changed:
-to some Liouvillian functions and for integration in terms of Ei, Si, Ci, li and
to some Liouvillian functions and for integration in terms of Ei, Si, Ci, li, erf,
fresnelS, fresnelC, Gamma and

added:


Errors in symbolic integration

Risch-Bronstein-Trager algorithm (Risch algorithm in short) is a complete algorithom for integration in terms of elementary functions. The algorithm either finds elementary integral or proves that there is none. Existence of elementary integral is relatively rare, so given random elementary function probably does not have elementary integral. FriCAS? implementation of Risch algorithm is probably the "most complete" existing implementation. Unfortunatly "most complete" does not mean complete, some parts are still unimplemented. Unlike some other systems FriCAS? will not give you unevaluated result when hitting unimplemented part. Instead, it signals error with message indicating that given integral requires unimplemented part. So when FriCAS? returns unevaluated result almost surely there is on elementary integral. Almost surely, because as all programs FriCAS? may have bugs...

FriCAS? in fact implements extension of Risch algorithm which extends class of integrands to some Liouvillian functions and for integration in terms of Ei, Si, Ci, li, erf, fresnelS, fresnelC, Gamma and polylog. While there is complete extended algorithm current FriCAS? implementation contains considerable gaps. Nevertheless, FriCAS? can handle a lot of examples involving special functions that no other system can handle.

Additionaly to Risch integrator FriCAS? contains releativlu weak pattern matching integrator which can generate a few special function -- in addition to Ei, Si, Ci, li it also can generate erf, fresnelC and fresnelS. However, if integral really requires elliptic functions then the best thing which FriCAS? can do is to prove that integral is nonelementary.

FriCAS? Examples

1)

fricas
integrate(sin(x)+sqrt(1-x^3),x)

\label{eq1}\int^{
\displaystyle
x}{{\left({\sqrt{-{{\%A}^{3}}+ 1}}+{\sin \left({\%A}\right)}\right)}\ {d \%A}}(1)
Type: Union(Expression(Integer),...)

Unevaluated result means that FriCAS? proved that result is not elementary and can not find nonelementary result.

int(sin(x)+sqrt(1-x^3),x);
reduce
\displaylines{\qdd
\frac{-5\cdot \cos 
      \(x
       

2)

fricas
integrate(sqrt(1-log(sin(x)^2)),x)
>> Error detected within library code: integrate: implementation incomplete (constant residues)

In this case FriCAS? neither can compute elementry result nor can it prove that result is not elementary, is it gives up with error message indicating that the handling this integral requires unimplemented part of Bronstein-Trager algorithm.

int(sqrt(1-log(sin(x)^2)),x);
reduce
\displaylines{\qdd
\int {\sqrt{
            -\ln 
            \(\sin 
              \(x
               

3)

fricas
integrate(sqrt(sin(1/x)),x)
>> Error detected within library code: integrate: implementation incomplete (constant residues)

Again, this integral needs unimplemented part of Bronstein-Trager algorithm.

int(sqrt(sin(1/x)),x);
reduce
\displaylines{\qdd
\frac{2\cdot 
      \sqrt{\sin 
            \(\frac{1}{
                    x}
             

4)

fricas
integrate(sqrt(sin(x)),x)

\label{eq2}\int^{
\displaystyle
x}{{\sqrt{\sin \left({\%A}\right)}}\ {d \%A}}(2)
Type: Union(Expression(Integer),...)

This time FriCAS? can prove that result is nonelementary (it needs elliptic functions).

int(sqrt(sin(x)),x);
reduce
\displaylines{\qdd
\int {\sqrt{\sin 
            \(x
             

For this Maple 9 gives the following result:


\label{eq3}
    -{\frac {\sqrt {1+\sin \left( x \right) }\sqrt {-2\,\sin \left( x
    \right) +2}\sqrt {-\sin \left( x \right) }}{\cos \left( x \right) \sqrt {\sin \left( x
    \right) }}} \times
    \
    \left( 2\,{\it EllipticE}
    \left( \sqrt {1+\sin \left( x \right) },1/2\,\sqrt {2} \right) -{\it 
    EllipticF} \left( \sqrt {1+\sin \left( x \right) },1/2\,\sqrt {2}
    \right)  \right)
    (3)

And Mathematica 4 gives:


\label{eq4}
    -2\,{\it EllipticE}(\frac{\frac{\pi }{2} - x}{2},2)
    (4)

symbolic integration
Tue, 22 Mar 2005 11:48:00 -0600 reply
fricas
integrate(exp(-x^2),x)

\label{eq5}{{\erf \left({x}\right)}\ {\sqrt{\pi}}}\over 2(5)
Type: Union(Expression(Integer),...)
Errorfunction
Wed, 23 Mar 2005 08:23:21 -0600 reply
fricas
integrate(exp(-x^2/2)/sqrt(%pi*2),x=%minusInfinity..%plusInfinity)

\label{eq6}{{\sqrt{2}}\ {\sqrt{\pi}}}\over{\sqrt{2 \  \pi}}(6)
Type: Union(f1: OrderedCompletion?(Expression(Integer)),...)

fricas
integrate(x,x)

\label{eq7}{1 \over 2}\ {{x}^{2}}(7)
Type: Polynomial(Fraction(Integer))

Works, roots remain unsimplified to preserve branches:

fricas
integrate(x^6*exp(-x^2/2)/sqrt(%pi*2),x=%minusInfinity..%plusInfinity)

\label{eq8}{{15}\ {\sqrt{2}}\ {\sqrt{\pi}}}\over{\sqrt{2 \  \pi}}(8)
Type: Union(f1: OrderedCompletion?(Expression(Integer)),...)
fricas
integrate(x^6*exp(-x^2/2)/sqrt(%pi*2),x)

\label{eq9}{{{15}\ {\sqrt{2}}\ {\erf \left({x \over{\sqrt{2}}}\right)}\ {\sqrt{\pi}}}+{{\left(-{2 \ {{x}^{5}}}-{{10}\ {{x}^{3}}}-{{30}\  x}\right)}\ {{e}^{-{{{x}^{2}}\over 2}}}}}\over{2 \ {\sqrt{2 \  \pi}}}(9)
Type: Union(Expression(Integer),...)

The answer should be:


\label{eq10}
15\,{\frac {\sqrt {\pi }}{\sqrt {\pi}}}
(10)

... --unknown, Thu, 25 Aug 2005 05:57:53 -0500 reply
fricas
integrate(exp(x)/x^2,x)

\label{eq11}{-{{e}^{x}}+{x \ {Ei \left({x}\right)}}}\over x(11)
Type: Union(Expression(Integer),...)

fricas
integrate(sqrt(x), x)

\label{eq12}{2 \  x \ {\sqrt{x}}}\over 3(12)
Type: Union(Expression(Integer),...)

fricas
integrate(a*x,x)

\label{eq13}{1 \over 2}\  a \ {{x}^{2}}(13)
Type: Polynomial(Fraction(Integer))